সহায়িকা

➡️ Step 1: Apply the Power Rule
 First, use the power rule of logarithms, \(n\log _{b}a=\log _{b}(a^{n})\), to simplify the first term:
\(2\log _{10}5=\log _{10}(5^{2})=\log _{10}25\)
➡️ Step 2: Combine Addition and Subtraction 
Next, use the product rule,
\(\log _{b}a+\log _{b}c=\log _{b}(ac)\), and the quotient rule, \(\log _{b}a-\log _{b}c=\log _{b}(a/c)\), to combine the terms:
\(\log _{10}25+\log _{10}36-\log _{10}9=\log _{10}\left(\frac{25\times 36}{9}\right)\)
➡️ Step 3: Simplify the Argument Calculate the value inside the logarithm:
\(\frac{25\times 36}{9}=25\times 4=100\)
This leaves us with:\(\log _{10}100\)
➡️ Step 4: Evaluate the Final Logarithm Since
\(10^{2}=100\),
the base-10 logarithm of 100 is:
\(\log _{10}100=2\)

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